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MATH 114 · Module 10 of 14

The Normal Distribution

Many real measurements — heights, test scores, measurement errors — follow a bell-shaped normal distribution. This module shows how to read it with the 68‑95‑99.7 rule and z-scores.

Learn the Concepts

1 · The 68‑95‑99.7 rule

A normal distribution is symmetric and bell-shaped, centered on its mean (μ) with spread set by the standard deviation (σ). The empirical rule says:

  • 68% of values fall within of the mean,
  • 95% within ,
  • 99.7% within .

The interactive explorer below lets you shade each band and see the percentages — it's the fastest way to build intuition for this module.

Learn the Concepts

2 · Z-scores

A z-score tells you how many standard deviations a value sits from the mean:

z = (x − μ) ÷ σ

A z-score of 0 is exactly average; z = +2 is two standard deviations above the mean (high); z = −1 is one below. Z-scores let you compare values from different normal distributions on a common scale.

Worked Examples

See it done, step by step

Example 1 — Test scores are normal with μ = 80, σ = 5. What percent scored 75 to 85?

75 = μ − σ and 85 = μ + σ, so this is the 1σ band.

That's 68% of students.

Example 2 — Men's heights are normal with μ = 70 in, σ = 3 in. What percent are 64 to 76 inches?

64 = μ − 2σ and 76 = μ + 2σ, the 2σ band.

That's 95% of men.

Example 3 — IQ scores have μ = 100, σ = 15. Find a z-score of 130.

Use z = (x − μ) ÷ σ.

z = (130 − 100) ÷ 15 = 30 ÷ 15 = 2 — two standard deviations above average.

Watch & Review

Resources for this module

Interactive

68‑95‑99.7 explorer

Shade each band, click segments for exact percentages, and use the z-score calculator.

Open explorer
Video

Using the 68‑95‑99.7 rule

A short walkthrough of empirical-rule problems.

Watch video
Slides

Lecture slides

The Module 10 slides on the normal distribution.

Open slides

Check Yourself

Quick self-check

1. About what percent of a normal distribution lies within 1 standard deviation of the mean?

About 68%.

2. A value has μ = 50, σ = 10, x = 35. Find its z-score.

z = (35 − 50) ÷ 10 = −1.5 (one and a half standard deviations below the mean).

3. Scores are normal with μ = 500, σ = 100. Between what scores do about 95% fall?

μ ± 2σ = 500 ± 200, so 300 to 700.

Ready to turn it in?

When the empirical rule and z-scores click, complete the Module 10 homework and quiz in Canvas.

Submit in Canvas