MATH 114 Module 10: The Normal Distribution
Outcomes: recognize a normal distribution; apply the 68–95–99.7 rule; compute standard scores; find and use percentiles.
1. The Normal Distribution
A normal distribution is symmetric and bell-shaped, with a single peak at its center. The mean, median, and mode are all equal at that peak. The standard deviation sets the width: a larger standard deviation gives a wider, flatter bell.
When to expect a normal shape
- Most values cluster near the mean, giving one well-defined peak.
- Values spread evenly around the mean, so the distribution is symmetric.
- Values far from the mean are rare, so the tails thin out.
- Many small factors (genes, environment, chance) shape the variable. Example: foot length is close to normal; scores on an easy test are not, because they pile up near 100 and are left-skewed.
2. The 68–95–99.7 Rule
In a normal distribution:
- about 68% of values lie within 1 standard deviation of the mean;
- about 95% lie within 2 standard deviations;
- about 99.7% lie within 3 standard deviations.
The pieces of the bell
Split each band in half, since the curve is symmetric:
- mean to 1 SD: 68 ÷ 2 = 34%
- 1 SD to 2 SD: (95 − 68) ÷ 2 = 13.5%
- 2 SD to 3 SD: (99.7 − 95) ÷ 2 = 2.35%
- beyond 3 SD on one side: (100 − 99.7) ÷ 2 = 0.15%
- each half of the curve: 50%
Method: draw the bell; label the mean, then mean ± 1, 2 and 3 SD; write 34, 13.5, 2.35 and 0.15 in the regions; add the regions the question asks for.
Example: legal quarters have a mean weight of 5.67 g with SD 0.07 g. A vending machine accepts only 5.53 to 5.81 g, which is mean ± 2 SD. It accepts about 95% and rejects about 5% of legal quarters.
3. Standard Scores (z-scores)
The standard score is the number of standard deviations a value lies above or below the mean:
z = (data value − mean) ÷ standard deviation- Positive z: above the mean. Negative z: below the mean. z = 0: at the mean.
- Example (IQ, mean 100, SD 15): 85 → z = (85 − 100)/15 = −1.00; 100 → z = 0; 125 → z = 25/15 ≈ 1.67.
- Working backward: data value = mean + z × standard deviation.
4. Percentiles
The percentile of a data value is the percentage of all values that are less than it. Find it from the z-score with the standard score table.
- z = −1 → 15.87th; z = 0 → 50th; z = 1 → 84.13th; z = 2 → 97.72nd.
- Percent above a value = 100% − its percentile. (Above z = −1: 100 − 15.87 = 84.13%.)
- Percent between two values = the larger percentile − the smaller one.
Example: cholesterol (mean 178, SD 41)
- Level 190: z = (190 − 178)/41 ≈ 0.29, which the table puts at about the 62nd percentile.
- 90th percentile: the table gives z ≈ 1.3 (90.32%), so the level is 178 + 1.3 × 41 ≈ 231.
5. Excel Online
=STANDARDIZE(x, mean, sd)gives the z-score.=NORM.DIST(x, mean, sd, TRUE)gives the fraction of values below x (multiply by 100 for the percentile).=NORM.INV(p, mean, sd)gives the value at a percentile (p as a decimal, such as 0.90).
Excel and the table can differ slightly in the second decimal place, because the table rounds z.
Resources
Lesson: andrewhvolk.github.io/courses/math114-module10.html · Slides: andrewhvolk.github.io/pdfs/math114-module10-slides-2026-10-26.pdf · Practice: Normal curve explorer and z-score calculator · Desmos Scientific and Excel Online
© Andrew H. Volk 2026