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Graph y = 10000(1.03)^x to watch an exponential model curve upward.
Open DesmosMATH 114 · Module 14 of 14
The last content module: modeling situations that change by a constant percentage rather than a constant amount, and knowing when an exponential model fits better than a linear one.
Learn the Concepts
An exponential model changes by a constant percentage each period, so it multiplies by a fixed factor:
Here P is the starting value, r is the percent change (as a decimal), and t is time. The factor (1 + r) is the growth factor; (1 − r) is the decay factor. Its graph curves rather than following a straight line.
Learn the Concepts
Choosing the right model comes down to one question: how does the quantity change?
Over time, exponential growth always overtakes linear growth, even if it starts slower — the curve eventually outruns any straight line.
Worked Examples
Growth factor is 1.03.
P(5) = 10000 (1.03)5 ≈ 10000 × 1.15927 ≈ 11,593 people.
Decay factor is 1 − 0.15 = 0.85.
V(3) = 20000 (0.85)3 = 20000 × 0.614125 ≈ $12,282.50.
Compute each model at t = 10.
Linear: 10000 + 1000(10) = $20,000.
Exponential: 10000 (1.10)10 ≈ $25,937.
The exponential model is far ahead — and the gap only widens.
Watch & Review
Graph y = 10000(1.03)^x to watch an exponential model curve upward.
Open DesmosRevisit the linear-vs-exponential comparisons from the growth quiz.
Open quizModule 14 slides and any posted videos are in your Canvas course.
Open CanvasCheck Yourself
1 − 0.20 = 0.80.
Growth at 4% per period (the factor 1.04 = 1 + 0.04).
Linear — a fixed amount is added each year, not a fixed percentage.
When you can model with exponentials and choose the right model, complete the Module 14 homework and quiz in Canvas. Next stop: the cumulative final review.
Submit in Canvas